5. Bulbs L1 and L2 are connected in parallel in the circuit, and the power supply voltage applied to both ends of them is 12V. If L1 resistance is 8 Ω and L2 resistance is 4 Ω, the current passing through L1 is 8 Ω_

5. Bulbs L1 and L2 are connected in parallel in the circuit, and the power supply voltage applied to both ends of them is 12V. If L1 resistance is 8 Ω and L2 resistance is 4 Ω, the current passing through L1 is 8 Ω_

Because it is a parallel circuit, U1 = U2 = u = 12 (V)
The current through L1 is: I1 = U1 / R1 = 12 / 8 = 1.5 (a)
A: slightly

There are two bulbs L1 and L2 in the parallel circuit. It is known that the resistance of L1 is greater than that of L2. Whose current is large?

Because they are in parallel, the voltages of the two bulbs are equal. According to I = u / R, the higher the resistance, the lower the current, and the higher the current of L2