The resistance values of two small bulbs L1 and L2 are 5 Ω and 10 Ω respectively. Connect them in series with a 6V power supply to calculate the current in the series circuit Speed, online, etc

The resistance values of two small bulbs L1 and L2 are 5 Ω and 10 Ω respectively. Connect them in series with a 6V power supply to calculate the current in the series circuit Speed, online, etc

According to Ohm's Law: I = u / r = u / (R1 + R2) = 6 / 15 = 2 / 5 = 0.4

A 1210 ohm bulb is connected to a home circuit and is energized for 10 seconds. How many J and how many degrees of electricity are consumed?

U & # 178; t / r = 220 & # 178; × 10 / 1210 = 400j, 1 kwh = 3.6 × 10 & # 179; × 10 & # 179;, so it is 1 / 9000 kwh

There are two resistors to connect them in series. The total resistance is 10 ohm and the parallel resistance is 2.1 ohm. What are the resistance values of these two resistors?

Let the resistance of one be x Ω and the other be y Ω. Then x + y = 10 (x * y) / (x + y) = 2.1, and x = 3, y = 7

Two resistors with resistance values of 1 ohm and 10 ohm are connected in parallel
A equals one euro
B is less than 1 ohm
C is greater than 1 ohm and less than 10 ohm
D is greater than 10 Ω
I want to choose B, but my classmates say choose C, what do you choose?

The resistance of a resistor with resistance value of a and B resistor in parallel: a * B / (a + b). As long as the formula of two resistors in parallel is applicable, it can be calculated. Here, 1 * 10 / (1 + 10) = 10 / 11, obviously less than 1