The relative atomic mass of a divalent metal element is () A. 24B. 40C. 56D. 64

The relative atomic mass of a divalent metal element is () A. 24B. 40C. 56D. 64

Suppose that the metal element is r, the mass of metal oxide is x.ro → R, the transfer electron is 1mol 2molx & nbsp; & nbsp; & nbsp; 0.2molx = 0.1mol, the molar mass of metal oxide is 4g0.1mol = 40g/mol, the relative molecular mass of metal oxide is 40, so the relative atomic mass of metal atom is 40-16 = 24, so a

The relative atomic mass of a divalent metal element is ()
A. 24B. 40C. 56D. 64

Suppose that the metal element is r, the mass of metal oxide is x.ro → R, the transfer electron is 1mol 2molx & nbsp; & nbsp; & nbsp; 0.2molx = 0.1mol, the molar mass of metal oxide is 4g0.1mol = 40g/mol, the relative molecular mass of metal oxide is 40, so the relative atomic mass of metal atom is 40-16 = 24, so a

Hydrogen is used to reduce a divalent metal oxide to make the metal element become a simple substance. When every 40g metal oxide is reduced, 1g hydrogen is consumed, what is the molar mass of the metal

I'm distrow. I have the wrong number. The answer hasn't been changed. It should be
RO+H2==H2O+R H2:R=1:1 n(H2)=1/2mol=n(RO)
So r is 64 g / mol