If the Al2 (SO4) 3 solution with Mg density of PG / cm3 contains SO42 ng, the mass concentration of the Al2 (SO4) 3 solution is 0

First, the volume of the solution is obtained by dividing the mass by the density, i.e. M / P (CM & # 179;). In the unit change, it becomes (M / P) × 10 - # 179; (L)
And then there is the amount of Al2 (SO4) 3: we use the mass of (SO4) 2 - to calculate the amount of (SO4) 2 - with the molar mass. We divide the mass by the molar mass, that is, N / 96 (mol). Then we use the ratio of Al2 (SO4) 3 to (SO4) 2 - to calculate the amount of (SO4) 2 - with the molar mass, that is, 1:3
1: So the amount of Al2 (SO4) 3 is n / 288 (mol)
Finally, there is a set of formula: the concentration of the amount of substance = the amount of substance / the volume of solution = (n / 288) / ((M / P) × 10 - (#) (mol / L)
The final value is 125 NP / 36 m (mol / L)

Under the standard condition, 500 volumes of HCl are dissolved in 1 volume of water to reach saturation, and the density of the solution is pg / ml, then the mass concentration of the solution is (mol / L)

n(HCl)=500/22.4
V=(1000 + 36.5*500/22.4)/p mL
c=n/V(L)

The density of the solution obtained by dissolving 700 volumes of HCl in 1 volume of water under standard conditions is pg / ml, and the concentration of the substance in the solution is calculated

If there is one liter of water, there will be 700 liters of hydrogen chloride
There are: the amount of hydrogen chloride is 700 / 22.4mol, the mass is 36.5 * 700 / 22.4g, the total mass of the solution is (36.5 * 700 / 22.4 + 1000) g, the volume of the solution is (36.5 * 700 / 22.4 + 1000) / 1000p, and the mass concentration of the obtained solution is 700 / 22.4 ÷ (36.5 * 700 / 22.4 + 1000) / 1000p = 7000p / (36.5 * 7 + 224) = 14.6p mol / L

If the Al2 (SO4) 3 solution with Mg density of PG / cm3 contains SO42 ng, the mass concentration of the Al2 (SO4) 3 solution is 0