When a solid ball with a density of 0.9 × 103kg / m3 is put into water and alcohol successively, the ratio of the volume of water discharged from the ball to the volume of alcohol discharged from the ball is________ What is the buoyancy ratio of the ball in water and alcohol______ (ρ = 0.8 × l03kg / m3) There are some on Baidu, but I can't understand them,

When a solid ball with a density of 0.9 × 103kg / m3 is put into water and alcohol successively, the ratio of the volume of water discharged from the ball to the volume of alcohol discharged from the ball is________ What is the buoyancy ratio of the ball in water and alcohol______ (ρ = 0.8 × l03kg / m3) There are some on Baidu, but I can't understand them,

Because the density of the ball is less than the density of the water, it floats, so the gravity of the ball is equal to the gravity of the water, and the mass of the ball is equal to the mass of the water, so the density of the water multiplied by the volume of the drained water = the density of the ball multiplied by the density of the ball, and because the density of the ball is greater than the density of the alcohol, it sinks, so it submerges, so the volume of the drained water equals the volume of the object, so the answer is 9:10, And because buoyancy equals density times G times the volume of the row, it goes without saying

The lower part of the container is a cube with a side length of 0.4m, and the upper part is a cube with a side length of 0.1M. The container is filled with liquid with a density of 0.8 × 103kg / m3 (excluding the weight of the container, G is 10N / kg),
(1) The pressure and pressure of the liquid on the bottom of the container;
(2) The pressure and pressure of the container on the table

The liquid density is 800 kg / m3, right? The shape of the container is two cubes stacked up and down,
The height of the container is 0.4 + 0.1 = 0.5m,
The bottom area of the container is 0.4x0.4 = 0.16 square meters,
The volume of the container is 0.4x0.4x0.4 + 0.1x0.1x0.1 = 0.064 + 0.001 = 0.065 cubic meters
The first step is to calculate the pressure of liquid on the container, which is liquid density X G x liquid depth h = 800 x 10 x 0.5 = 4000 PA
The second step is to calculate the pressure of the liquid on the container, which is liquid pressure x bottom area = 4000 x 0.16 = 640 n
The third step is to calculate the pressure of the container on the table. The weight of the container is not included, so the mass of the liquid is calculated,
Density x volume = 800 x 0.065 = 4 x 2 x 6.5 = 4 x 13 = 52 kg
Pressure = gravity = 52 x 10 = 520 n
The fourth step is to calculate the pressure of the container on the table, which is the pressure / bottom area of the container = 520 n / 0.16 M2 = 3250 PA
Solid pressure, liquid pressure, the two are completely different, we should pay attention to distinguish ah

A cube of rubber clay with a side length of 4cm and a density of 2 × 103kg / m3 is put into enough water to sink into the bottom, The following calculation results are correct: a. the mass of the rubber clay is 12.8gb. The buoyancy of the rubber clay when immersed in water is 1.28nc. The buoyancy of the rubber clay boat when floating is 0.64nd. The volume of water discharged by the rubber clay boat when floating is 1.28 × 10-4m3

Choose D

Aluminum is a kind of less dense metal. In recent years, scientists have developed lighter aluminum foam aluminum. The density of some aluminum foam is only 0.18 x 103Kg/m3., immersing a heavy 10N aluminum foam in water. &When it is still, the buoyancy it receives is______ N．

foam aluminum immersed in water, buoyant force: F float = water V row g= g= water V aluminum g, foam aluminum weight: G=, aluminum, V, aluminum, G, water, P, aluminum, F F, float, G, foam aluminum will float up, when foam aluminum is stationary, float, and the solution is floating.