A light bulb is marked with "4V, 4W". After it is connected in series with a constant resistance R, it is connected into the circuit with the power supply voltage of 6V. When the switch is closed, measure the A bulb is marked with the words "4V, 4W". After it is connected in series with a constant resistance R, it is connected to the circuit with the power supply voltage of 6V. When the switch is closed, the measured power consumption of R is 2W. At this time, the bulb does not light normally. Regardless of the influence of temperature on the resistance value of the bulb, calculate: 1 the resistance value of the constant resistance R, 2 the incident electric power of the bulb

A light bulb is marked with "4V, 4W". After it is connected in series with a constant resistance R, it is connected into the circuit with the power supply voltage of 6V. When the switch is closed, measure the A bulb is marked with the words "4V, 4W". After it is connected in series with a constant resistance R, it is connected to the circuit with the power supply voltage of 6V. When the switch is closed, the measured power consumption of R is 2W. At this time, the bulb does not light normally. Regardless of the influence of temperature on the resistance value of the bulb, calculate: 1 the resistance value of the constant resistance R, 2 the incident electric power of the bulb

Bulb resistance = u * U / P = 4 * 4 / 4 = 4 Ω
If the resistor voltage ur is set in series, then the bulb voltage is 6-ur
So: I = (6-ur) / 4;
R consumption 2W, I * ur = 2,
Ur(6-Ur)/4=2
Ur^2-6Ur+8=0
Ur=4V
Ir=P/Ur=2/4=0.5A
R=Ur/Ir=4/0.5=8Ω
Actual power of bulb = 0.5 * 2 = 1W

What is the difference between the experiment of measuring the electric power of small bulb and the experiment of measuring the resistance of small bulb

The principle is different: P = UI, r = u / I; measure the resistance of the small bulb, take the average value three times to reduce the error, measure the electric power of the small bulb: the rated voltage is less than the actual voltage, the rated voltage is equal to the actual voltage, and the electric power when the rated voltage is greater than the actual voltage
The same point, both circuit diagram is the same

"Measuring the resistance of small bulb", "measuring the electric power of small bulb" and "exploring the relationship between current and voltage on conductor"

I don't quite understand what you mean. According to my understanding, every sentence is a problem, how to measure it. 1. Measure the resistance of a small bulb - use the resistance gear of a multimeter to measure the cold resistance of a small bulb. 2. Measure the electric power of a small bulb - use a voltmeter and an ammeter to measure the voltage and current, and the product is the electric power

How to measure the resistance and power of a small bulb?
YHANK YOU

First, draw the circuit diagram, check whether the principle of the circuit diagram is correct. The diagram is not drawn, a brief introduction, battery, switch, small bulb, sliding rheostat constitute a simple series circuit, ammeter in series in the circuit, voltmeter and bulb in parallel. 2, according to the circuit diagram