In the series circuit, the rated voltage of a small bulb is 2.4V, and the resistance is 8 when the lamp is normally emitting. If there is only 3V power supply, if the bulb is normally emitting What is the resistance in series? (common series circuit)

In the series circuit, the rated voltage of a small bulb is 2.4V, and the resistance is 8 when the lamp is normally emitting. If there is only 3V power supply, if the bulb is normally emitting What is the resistance in series? (common series circuit)

2.4/8=0.3A
3 / 0.3 = 10 ohm
10-8 = 2 ohm
A 2 ohm resistor needs to be connected in series

A small bulb, when the voltage at both ends of it is below 3V, the resistance can be approximately equal to 14 Ω unchanged: when the voltage at both ends of it increases to 4V
When the voltage increases to 5V, its resistance is 19 Ω. What is the volt ampere characteristic curve in the range of 0-5V? Please draw a sketch

1-3v is an inclined line
The process of 3-5v is a curve with larger and larger slope, that is, upward bias
I drew it by hand with a computer,

When the small bulb lights normally, the resistance of the filament is 6 Ω, and the rated voltage is 2V. If the power supply voltage is 6V, how much resistance should be connected in series to make the small bulb light normally

If the small bulb wants to light normally, the voltage is 2V
series connection
U=U1+U2
be
The resistance voltage in series is U2 = u-u1 = 6v-2v = 4V
Bulb current: I1 = U1 / R1 = 2V / 6 Ω = 1 / 3A
Series connection, equal current, I2 = I1 = 1 / 3A
R2=U2/I2=4V/(1/3A)=12Ω

A small bulb filament resistance 8 ohm, voltage 3.2V, has a 6V power supply and some resistors, how to make it shine? There are several methods?

Just choose the right resistor in series with the bulb. Remember that these resistors share 2.8V voltage