The light bulb in the home circuit will be dimmed if it is used for a long time. The one that can make the light bulb brighter is a. replace it with a bigger light bulb. B. replace the dry battery of the flashlight C change to a new battery d change to a smaller bulb

The light bulb in the home circuit will be dimmed if it is used for a long time. The one that can make the light bulb brighter is a. replace it with a bigger light bulb. B. replace the dry battery of the flashlight C change to a new battery d change to a smaller bulb

According to the options you provide, the title should be:
If the battery in the flashlight circuit is used for a long time, the brightness of the light bulb will be dimmed. What can make the light bulb bright is: (C. replace with a new battery)
Note: if the battery in the flashlight circuit is used for a long time, the luminous brightness of the bulb will be dimmed, because the voltage of the battery is reduced and the power of the bulb is reduced. Therefore, only by using a new battery can the power of the bulb be improved and become brighter

The two dry batteries in the flashlight have been used for a long time. When they are used, the small light bulb can only emit very weak light. Take them out and measure the voltage with a voltmeter. The voltmeter's indication is very close to 3V. Then use them as the power supply of a desk electronic clock. The electronic clock can work normally
A. The electromotive force of these two dry batteries is reduced a lot. B. the internal resistance of these two dry batteries increases a lot. C. the rated voltage of this electronic clock must be lower than that of the small bulb in the flashlight. D. the current of this electronic clock must be lower than that of the small bulb when it works normally

A. The electromotive force of these two dry batteries should be 3V, and now the direct voltage expression is very close to 3V. It can be seen that the electromotive force is almost unchanged, so a is wrong; B. the two dry batteries have been used for a long time, and the small bulb can only emit very weak light. In addition to the decrease of electromotive force, the internal resistance of the battery increases. If it is larger than the resistance of the bulb, the output voltage is very small Correct; C, the table electronic clock can work normally because its internal resistance is much larger than that of the battery, so the output voltage is higher, so it can work, so C is wrong; D, because the resistance of the electronic clock is larger, so the normal working current is smaller, so D is correct; so BD is selected

The two dry batteries in the flashlight have been used for a long time. When they are used, the small light bulb can only emit very weak light. Take them out and measure the voltage with a voltmeter. The voltmeter's indication is very close to 3V. Then use them as the power supply of a desk electronic clock. The electronic clock can work normally
A. The electromotive force of these two dry batteries is reduced a lot. B. the internal resistance of these two dry batteries increases a lot. C. the rated voltage of this electronic clock must be lower than that of the small bulb in the flashlight. D. the current of this electronic clock must be lower than that of the small bulb when it works normally

A. The electromotive force of these two dry batteries should be 3V, and now the direct voltage expression is very close to 3V. It can be seen that the electromotive force is almost unchanged, so a is wrong; B. the two dry batteries have been used for a long time, and the small bulb can only emit very weak light. In addition to the decrease of electromotive force, the internal resistance of the battery increases. If it is larger than the resistance of the bulb, the output voltage is very small Correct; C, the table electronic clock can work normally because its internal resistance is much larger than that of the battery, so the output voltage is higher, so it can work, so C is wrong; D, because the resistance of the electronic clock is larger, so the normal working current is smaller, so D is correct; so BD is selected

The two dry batteries of the flashlight have been used for a long time. The small light bulb can only emit weak light. Take them out and measure the voltage with a voltmeter. The voltage indicates the number
It is close to 1.5V. If they are installed in the electronic clock, the electronic clock can work normally. This phenomenon is explained by Ohm's law of closed circuit

The battery which has been used for a long time has a large internal resistance, that is, R is very large
According to Ohm's law e = I (R + R), when the internal resistance is very large, the voltage that the battery is connected to the circuit and distributed to the external circuit is very small, so the small bulb emits weak light. However, if the voltmeter is used, because the internal resistance of the voltmeter is very large, almost all the voltage is divided, so the indication is close to 1.5V