How much a is the transmission current for the transmission of 220kw electric power with 110kV high-voltage transmission? If the transmission voltage is 220V, how much a is the transmission current, and how many times the power loss of the latter transmission line is that of the former?

How much a is the transmission current for the transmission of 220kw electric power with 110kV high-voltage transmission? If the transmission voltage is 220V, how much a is the transmission current, and how many times the power loss of the latter transmission line is that of the former?


220000 / 110000 = 2A, then 220000 / 220 = 1000A, according to P = I2R, the power loss is 250000 times of the former



The output voltage of the power plant is 3300 V, the power transmitted is 3300 kW, the resistance of the transmission line is 2 ohm, the heating power is? Loss rate?


P=I^2R I=P/U=3300000/3300=1000A P=2000000 W=2000KW=2MW
Loss power n = 2 / 3.3 = 61%
There may be something wrong with your data. It is estimated that the output voltage should be higher, otherwise the loss rate is too high



If the transmission voltage is 1100V and 22000v respectively, if the transmission power is the same, the material and distance of the conductor are also the same, then when the power loss of the two transmission is equal, the ratio of the cross-sectional area of the conductor used in the two transmission is ()
A. 1:20B. 20:1C. 1:400D. 400:1


Suppose the resistivity of the conductor is ρ, the cross-sectional area of the conductor is s, the total resistance of the conductor is r, the transmission distance is l, the transmission voltage is u, the current in the transmission line is I, and the transmission power is p, then we can get it from P = UI, I = Pu, the electric power loss of transmission is △ P = I2R, r = ρ 2LS, and get △ P = p2u2 ·ρ 2LS



The electric power transmitted by the power supply is p, the total resistance of the transmission line is r, and the thermal power lost by the current on the transmission line is P1


The output power of the power supply P total = P + P1; at this time, the circuit current is I = p1r; the output voltage of the power supply u = P total I = P + p1r = (P + P1) p1rp1. Answer: the output voltage of the power supply is (P + P1) p1rp1