The internal resistance of the generator is r = 0.1 ohm, the load resistance is r = 22 ohm, the current in the circuit is I = 10a, and the resistance of each connecting wire is RL = 0.1 ohm What is the electromotive force of the engine What is the output power of the power supply What is the power of the engine

The internal resistance of the generator is r = 0.1 ohm, the load resistance is r = 22 ohm, the current in the circuit is I = 10a, and the resistance of each connecting wire is RL = 0.1 ohm What is the electromotive force of the engine What is the output power of the power supply What is the power of the engine

1)E=I*(r+R+2Rl)=10*22.3=223V
2)p=(R+2Rl)*I*I=22.2*10*10=2220 W
3)p=EI=2230 W

If the AB resistance is 4 ohm, the ratio of the length of the long and short arcs is 0
I'm dizzy if I can't pass the picture
Just a circle AB inscribed (almost like an edge of an equilateral triangle) triangle

R = ρ L / S ratio of length = ratio of resistance. If two arcs are regarded as two resistors, that is, two resistors are connected in parallel. The total resistance in parallel is 4 Ω. If the resistance of one arc is r, then the other arc is R '= 18-r1 / R total = 1 / R + 1 / R'1 / 4 = 1 / R + 1 / (18-r) r = 12 Ω or r = 6 Ω, R' = 18-r = 6 Ω or R '= 1

When the electric furnace is working, its resistance wire is red hot, but the wire connected with the resistance wire is not very hot. What's the reason?

When the electric furnace is in use, the resistance wire is connected in series with the wire, I resistance wire = I wire, the power on time t is the same, ∵ q = i2rt, R resistance wire > R wire, and the heat generated by the current: Q resistance wire > Q wire, thus the resistance wire is red when the electric furnace is working, but the connected wire is not very hot. A: This is because the resistance wire is connected in series with the wire, and the resistance wire is electrically heated Resistance is greater than wire resistance, and current generates more heat on resistance wire

How many ohms is the resistance of a kilowatt furnace wire

Power = voltage squared / resistance
1000 = 220 * 220 / resistance
Resistance = 220 * 220 / 1000 = 48.4 ohm
The answer is 48.4 ohm