A certain electric blanket has only one gear, which is inconvenient to use. Xiao Ming wants to use a resistor as a heater in series with it, and transform it into an electric blanket with two gears It is known that the rated power of the original electric blanket is 220 v. in order to measure its rated power, Xiao Ming connected it in series with a bulb marked "220 V 25 W" in the home circuit, and measured the voltage of the small bulb to be 176 v. (the power supply voltage is constant, regardless of the influence of temperature on the resistance) 1. What is the rated power of the original electric blanket? 2. In order to make the total heating power of the reformed electric blanket in low gear three fifths of the rated power of the original electric blanket, what resistance wire does Xiao Ming need? (hope to get the solution process,

A certain electric blanket has only one gear, which is inconvenient to use. Xiao Ming wants to use a resistor as a heater in series with it, and transform it into an electric blanket with two gears It is known that the rated power of the original electric blanket is 220 v. in order to measure its rated power, Xiao Ming connected it in series with a bulb marked "220 V 25 W" in the home circuit, and measured the voltage of the small bulb to be 176 v. (the power supply voltage is constant, regardless of the influence of temperature on the resistance) 1. What is the rated power of the original electric blanket? 2. In order to make the total heating power of the reformed electric blanket in low gear three fifths of the rated power of the original electric blanket, what resistance wire does Xiao Ming need? (hope to get the solution process,

Resistance of small bulb R1 = 220 ^ 2 / 25 = 1936 Ω I = 176 / 1936 = 0.091a resistance of electric blanket r = (220-176) / 0.091 = 484 Ω power of electric blanket P = 220 ^ 2 / 484 = 100W voltage on R after transformation [(100 * 3 / 5) * 484] ^ 0.5 = 170.4v resistance wire R2 = (220-170.4) / (170.4 / 484) = 140.9Ω

A certain electric blanket has only one gear, which is inconvenient to use. Xiao Ming wants to use a resistance wire as a heater in series with it and change it

Is this topic: a certain electric blanket has only one gear, which is inconvenient to use. Xiaoming wants to use a resistance wire heater in series with it to transform it into an electric blanket with two gears. It is known that the rated voltage of the original electric blanket is 220 v. in order to determine its rated power, Xiaoming wants to connect it with a light bulb marked "220 V.25 W" in series in the home

Xiaoming wants to use a resistance wire as a heating body in series with it, and transform it into an electric blanket with two gears. It is known that the rated voltage of the original electric blanket is 220 v. in order to determine its rated power, Xiaoming combines it with an electric blanket marked "220 V & nbsp; 25W "bulb in series in the home circuit (as shown in Figure 1), the voltmeter indication is 176v. (the power supply voltage is constant at 220V, regardless of the influence of temperature on the resistance) to find: (1) what is the rated power of the original electric blanket? (2) In order to make the total heating power of the modified electric blanket (as shown in Figure 2) in low temperature gear three fifths of the rated power of the original electric blanket, what resistance wire does Xiaoming need? (keep one decimal place) (3) how much energy does R0 consume when the reformed electric blanket works for 10 minutes at low temperature?

(1) Bulb resistance RL = u2pl = (220V) 225W = 1936 Ω, voltage at both ends of R0 U0 = u-ul = 220v-176v = 44V, because R0 is in series with bulb L, R0 = u0ulrl = 44v176v × 1936 Ω = 484 Ω

In the circuit diagram, how to see the slide of sliding rheostat moving left, the resistance becomes smaller; moving right, the resistance becomes larger; or moving left, the resistance becomes larger, and moving right, the resistance becomes smaller?

The correct way to connect the sliding rheostat into the circuit is to connect the terminal one up and one down into the circuit. The change of the resistance of the sliding rheostat into the circuit mainly depends on the lower terminal. If the lower terminal is connected to the left, the effective resistance of the sliding rheostat into the circuit is on the left. When the slide moves to the left, the effective length of the resistance wire