Using Thevenin's theorem to find the current I of 2 Ω resistor in the circuit

Using Thevenin's theorem to find the current I of 2 Ω resistor in the circuit

First, the current source is converted to the voltage source mode
Us = 5 * 5 = 25 V
R = 5 + 10 = 15 Ω
I1 = (25 - 10) / (15+3) = 5/6 A
Uab = 20 + 3 * 5/6 = 22.5 V
Rab & nbsp; = & nbsp; 15 & nbsp; * 3 & nbsp; / (15 + 3) & nbsp; = & nbsp; 2.5 & nbsp; Ω & nbsp; & nbsp; & nbsp;; voltage source short circuit, resistance parallel
I = Uab / (Rab + 2) = 22.5 / 4.5 = 5 A

Try to use Thevenin's theorem to find the current I through a 10 ohm resistor in the circuit shown in the figure

The 10 ohm branch is removed, and the voltage source of each branch is converted into a current source. After merging, it is converted into a voltage source