The resistance values of the two resistors are R1 = 8 ohm and R2 = 4 ohm. If they are connected in series with a 24 V power supply, the voltage at both ends of R1 is (), the voltage at both ends of R2 is (), and the total current of the circuit is Please explain the method,

The resistance values of the two resistors are R1 = 8 ohm and R2 = 4 ohm. If they are connected in series with a 24 V power supply, the voltage at both ends of R1 is (), the voltage at both ends of R2 is (), and the total current of the circuit is Please explain the method,

Total current
I=U\R=24V\8Ω+4Ω=2A
R1 voltage
U1 = I times R1 = 2A times 8 Ω = 16V
R2 voltage
U2=U-U1=24V-16V=8V

If the three resistors R1, R2 and R3 are 2.4 and 9 ohm respectively, when they are connected in series in the circuit, the ratio of current is? And the ratio of voltage is?
When they are connected in parallel in the circuit, the voltage ratio is? And the current ratio is? Yes, plus a reward

Series connection in circuit
The current ratio is 1:1:1
v=IR
Voltage ratio = 2:4:9

After resistor R1 and R2 are connected to the circuit in series, the voltage applied at both ends is 24 v. if R1 = 80 ohm, the current passing through R1 is 0.2A, R2 is calculated

U1+U2=24v
U1=R1*I
=80*0.2=16V
U2=8v
U2=R2*I
R2=40Ω

After resistor R1 and R2 are connected to the circuit in series, the voltage applied at both ends is 24 v. if R1 is 80 Ω, the current passing through R2 is 0.2 a, R2 can be calculated. Can you find out the answer in two ways?

Method 1: ∵ the current in all parts of the series circuit is equal, ∵ according to Ohm's law, the total resistance in the circuit is r = UI = ui2 = 24v0.2a = 120 Ω, ∵ the total resistance in the series circuit is equal to the sum of the partial resistances, ∵ R2 = r-r1 = 120 Ω - 80 Ω = 40 Ω. Method 2: ∵ the current in all parts of the series circuit is equal, ∵ according to Ohm's law, the voltage at both ends of R1 is U1 = i1r1 = i2r1 = 0.2A × 80 Ω = 16 5. ∵ the total voltage in the series circuit is equal to the sum of the partial voltages, and the voltage at both ends of R2: U2 = u-u1 = 24 V-16 v = 8 V, then R2 = u2i2 = 8 V 0.2A = 40 Ω. Answer: the resistance value of R2 is 40 Ω