The name plates of the two lamps are marked with "220 V, 100 W" and "220 V, 25 W" respectively“ When a lights up normally, the electric power of lamp a is four times that of lamp B When B lights up normally, class a consumes four times as much electricity as class B

The name plates of the two lamps are marked with "220 V, 100 W" and "220 V, 25 W" respectively“ When a lights up normally, the electric power of lamp a is four times that of lamp B When B lights up normally, class a consumes four times as much electricity as class B

When a lights up normally, the electric power of a lamp is four times that of B lamp
B. the power consumed is related to time, wrong

If the electrical appliances of Party A are marked with "220 V 100 W" and the electrical appliances of Party B are marked with "110 V 60 W", they all work under the rated voltage, the following statement is correct:
A. It takes the same amount of time to complete the same work for dual-purpose electrical appliances. B. in the same time, the second electrical appliance must complete more work

According to the formula w = Pt, because P is different, W is different at the same time, so a is wrong
Because the power of B is small, the work done by B's electric appliance must be less in the same time, so B is wrong

A small bulb marked with 220V 100W L4, which works normally for 40 hours, how many kilowatt hours does it consume?

100 * 40 = 4000 Watt hours = 4 degrees

If an electric iron is marked with the word "220 V 100 W", how many hours can it normally work with 1 kilowatt hour of electricity? It can be powered on for 10 hours under the rated voltage
How much heat does it produce

Because w = Pt, t = w / P = 1000W * H / 100W = 10h, from the 220V 100W, the rated current of electric iron is 0.45a, and the resistance is 484 ohm. So the heating q = I ^ 2rt = (0.45) ^ 2 times 484 ohm times 600s = 58806 Joule (this is not necessarily accurate, but the number is too large, but the idea must be right) all give you answers