There is an electrical appliance with a resistance of 121 ohm at 220 V and 400 W. if the voltage is 380 V, how small is the resistance to be equal to 400 W? Please explain the reason

There is an electrical appliance with a resistance of 121 ohm at 220 V and 400 W. if the voltage is 380 V, how small is the resistance to be equal to 400 W? Please explain the reason

I ＝P/U
R＝U / I
The current of 400w380v consumer is:
400(W)/380(V)≈1.0526(A)
So its resistance is:
380(V)/ 1.0526(A)≈361(Ω)

There is an electrical appliance with a resistance of 121 ohm at 220 V and 400 W. if the voltage is 380 V, how small is the resistance to be equal to 400 W?
How small is it? Please explain why

361 Euro

The lamp L1 marked with pz220 25 and the lamp L2 marked with pz220 100 are connected in series in the home circuit. After the circuit is connected, the power ratio of the two lamps is 0_ Actual power of lamp L1
Is its rated power_ The actual power of L2 is equal to the rated power_ The total power of the two lamps is_

R1 = 220 square / 25 = 1536 ohm, I1 = u / R1 = 0.14a (approximately), R2 = 220 square / 100 = 484 ohm, I2 = u / r2 = 0.45a (approximately). After series connection, u = 220 remains unchanged, total resistance R = 1536 + 484 = 2020 ohm, total current I = 220 / 2020 = 0.1089ap1 = I square * R1 = 0.1089 * 1536 = 18.2w, P2 = I

There is a small bulb marked "pz220 - 40" connected to the 200V home circuit
(1) Find out the resistance R and current I when the bulb is normally emitting light. (2) how long can 1kW · h electric energy supply the bulb to work normally. (3) if the actual voltage is 220V, what is the actual power of the bulb? What is the luminous condition of the bulb? What is the rated power of the bulb
The steps must be more specific! Please! Hurry up! Today's homework! ~ ~!

(1) When r = 1.616 Ω, I = 0.2A (2) can be used for 22.75 hours (3), the actual power is 40W, the luminous intensity is enhanced, and the rated power of the bulb is 40W