An incandescent lamp marked with 220V 100W lights normally The resistance of an incandescent lamp marked with "220V 100W" is______ Ω; "220 V 100 W" incandescent lamp and "220 V 20 W" energy-saving lamp work normally with the same brightness. If both lamps work normally, they consume 1 kW and 8226; h electric energy respectively, and the energy-saving lamp works more than the incandescent lamp______ h. Energy saving lamp is more economical than incandescent lamp____ %The power of the power

An incandescent lamp marked with 220V 100W lights normally The resistance of an incandescent lamp marked with "220V 100W" is______ Ω; "220 V 100 W" incandescent lamp and "220 V 20 W" energy-saving lamp work normally with the same brightness. If both lamps work normally, they consume 1 kW and 8226; h electric energy respectively, and the energy-saving lamp works more than the incandescent lamp______ h. Energy saving lamp is more economical than incandescent lamp____ %The power of the power

The power of 40W bulb refers to the unit time; you can use it to see that the rated voltage of the bulb is less than 20V, if not, then do not use it. The lamp has the rated voltage of 220V, 110V, 36V, 24V, 12V, 6.3V, 3V, 1.5V, as long as it is not connected with the rated voltage line, it can be used when not in use

Junior high school electricity problem: a light bulb 220v100w connected in the circuit is not too bright, the actual electric power is 81w, the circuit voltage does not change, the electric power consumed on the 220 V ball wire

Rated voltage and rated power are uo = 220 V, Po = 100 W, actual power P = 81, WP = UI = u * U / r = u ^ 2 / RP / PO = [u ^ 2 / R] / [uo ^ 2 / R] = (U / UO) ^ 2U / uo = (P / PO) ^ 1 / 2 = (81 / 100) ^ 1 / 2 = 0.9u = 0.9uo = 0.9 * 220 = 198v, voltage on conductor is u '= uo-u = 220-198 = 22V, current in conductor is I' = lamp actual

There are two light bulbs, which are marked with 220v40w and 220v100w respectively. In ordinary parallel circuit and series circuit, which one is brighter

The resistance of 220v40w is set to r1220v100w is set to R2
There is a formula: r = u ^ 2 / P to get R1 > R2
Parallel connection: because the voltage at both ends of the bulb is equal, there is a formula P = u ^ 2 / R to get P1

When a "220 V 100 W" light bulb is connected to a 220 V circuit, the wire consumes 6 W of power. Is the actual power of the light bulb 94 w

220v100w "bulb
The actual power of the bulb is 100W