A truck, the engine power is 70kw, the total weight of the car and goods is 5T, in the form of uniform speed on a straight road for 10min Ask (1) how much work did the car's engine do during this journey? (2) the resistance the car is subjected to

A truck, the engine power is 70kw, the total weight of the car and goods is 5T, in the form of uniform speed on a straight road for 10min Ask (1) how much work did the car's engine do during this journey? (2) the resistance the car is subjected to

What power do you mean, rated power or actual power
If it is the actual power, w = Pt = 7000W * 600s
(2) Less conditions, right?

The engine power of the truck is 70kw, and the total mass of the truck and goods is 5T. Driving on a straight road, the truck has advanced 6kW in 10 minutes. What is the resistance of the truck?

The answer is 16S
(1) The maximum velocity is p / F = 60 * 103 / 5.0 * 103 (i.e. the third power of 10, the same below) = 12m / s
(2) According to P = f * V (f-f) / M = 0.5, f = 7.5 * 103
So v = P / F = 8 at = 8 T = 16S