Two fixed value resistors R1 and R2 are connected in parallel and connected to the circuit. Their electric power is P1 and P2 respectively, and the total power is p. try to prove that P = P1 + P2

Two fixed value resistors R1 and R2 are connected in parallel and connected to the circuit. Their electric power is P1 and P2 respectively, and the total power is p. try to prove that P = P1 + P2

It is proved that: ∵ the voltage u at both ends of each branch in parallel circuit is equal, ∵ after two fixed value resistors R1 and R2 are paralleled, the voltage at both ends of them is u, ∵ the main circuit current in parallel circuit is equal to the sum of each branch current, i.e. I = I1 + I2, ∵ according to P = UI, P = UI = u (I1 + I2) = ui1 + ui2 = P1 + P2, i.e. P = P1 + P2

Given that the sum of the two resistors is 20 ohm, parallel the two resistors R1 and R2, and calculate the maximum value after parallel connection

5 ohm
It's very simple, r = R1 * R2 / (R1 + R2) = R1 * R2 / 20
The maximum time is 10 * 10, so it is 5 ohm

When R1 and R2 are connected in series, the total resistance is 15 ohm, and when they are connected in parallel, the total resistance is 3.6 ohm=____ Ohm, R2____ Ohm
The sooner you answer, the better

According to the solution of "R1 + R2 = 15" and "(1 / R1) + (1 / r2) = (1 / 3.6)"
"R1 = 6 Ω, R2 = 9 Ω or R1 = 9 Ω, R2 = 6 Ω“

In the circuit with a resistance mixed connection, R1 = 30 ohm, R2 = 60 ohm, and then connected in parallel with R3 = 10 ohm, how much is the total resistance?

30
30*60/(30+60) +10