In equilateral triangle circuit, corresponding to three resistors, known as U1 = U2 = U3 = 380V, R1 = R2 = R3 = 48 ohm, calculate I1, I2, I3

In equilateral triangle circuit, corresponding to three resistors, known as U1 = U2 = U3 = 380V, R1 = R2 = R3 = 48 ohm, calculate I1, I2, I3

When each phase load △ is connected, the line voltage is equal to the phase voltage, and the phase current IX = 380 △ 48 = 7.92a,
Line current I1 = I2 = I3 = II = √ 3 × IX = 13.71a

I1: I2 = R2: R1 (parallel circuit) and U1: U2 = R1: R2 (series circuit) in Ohm's law of partial circuits
Give me a detailed description, the points are big

Parallel circuit U1 = U2, u = IR, i1r1 = i2r2, I1: I2 = R2: R1
Series circuit I1 = I2, I = u / R. U1 / R1 = U2 / R2, I1: I2 = R1 / R2

Resistance R1 = 24 ohm. If a 20 ohm resistance R2 is paralleled on R1, the current in the main circuit is 0.55a. Calculate the power supply voltage and the current intensity through R1

R = R1 * R2 / R1 + R2 = 24 * 20 / 24 + 20 = 120 / 11 ohm
U=IR=6V
I1=(R2/R1+R2)*I=0.25A

How to express the symbol of force in letters?

N