In the circuit shown in the figure, both ammeter and voltmeter are ideal ammeter, then the correct one in the following judgment is () --- the one that can understand (A) Rab = RBD, and RBC is the largest, RAC is the smallest, (B) Rab = RCD, and RBC is the largest, RAC is the smallest, (C) RAC = RCD, and RBC is the largest, RAD is the smallest, (D) RAC = RBD, and RBC is the largest, RAD is the smallest, -- see -- the answer is C. I don't quite understand. If the answer is the same, please forgive me for ignoring it

In the circuit shown in the figure, both ammeter and voltmeter are ideal ammeter, then the correct one in the following judgment is () --- the one that can understand (A) Rab = RBD, and RBC is the largest, RAC is the smallest, (B) Rab = RCD, and RBC is the largest, RAC is the smallest, (C) RAC = RCD, and RBC is the largest, RAD is the smallest, (D) RAC = RBD, and RBC is the largest, RAD is the smallest, -- see -- the answer is C. I don't quite understand. If the answer is the same, please forgive me for ignoring it

D

In the circuit shown in the figure, the internal resistance of power supply can not be ignored. Both ammeter and voltmeter are ideal ammeter
A. If R1 is short circuited, the number of current indication decreases and the number of voltage indication increases. B. If R2 is short circuited, the number of current indication decreases and the number of voltage indication increases. C. If R3 is open circuited, the number of current indication decreases and the number of voltage indication increases. D. if R4 is open circuited, the number of current indication decreases and the number of voltage indication increases

A. If R1 is short circuited, its resistance is zero, and the reading of the voltmeter in parallel is zero. If the resistance of the parallel part decreases, it can be seen from the "series reverse parallel same" that the number of current indication decreases; therefore, a is correct; B. If R2 is short circuited, the external resistance decreases, the terminal voltage decreases, and the current through R3 decreases, then the number of current indication decreases. If the total current of R1 and R3 is i13, the total current increases, and the current through R4 decreases So B is correct. C. If R3 is open circuit, the number of current is zero, the external resistance increases and the terminal voltage increases, then the reading of voltmeter increases. D. if R4 is open circuit, the external resistance increases and the terminal voltage increases, then the reading of ammeter and voltmeter increases So D error. So selected: ABC

In the circuit shown in the figure, the ammeters at (1), (2), (3) and (4) are ()
A. Meter 1 is a voltmeter, meter 2, meter 3, meter 4 is an ammeter B. meter 1, meter 3 is a voltmeter, meter 2, meter 4 is an ammeter C. meter 1, meter 2, meter 3, meter 4 is an ammeter D. meter 1, meter 3, meter 4 is a voltmeter, meter 2 is an ammeter

It can be seen from the circuit diagram that in order to make the bulb shine, the meter in series with the bulb should be an ammeter, the meter in parallel with the bulb is a voltmeter, and the meter in series on the trunk road is an ammeter, so the meter in series is an ammeter and the meter in series is a voltmeter

As shown in the figure, in the circuit, the resistance value of resistance R1 is 20 Ω, close the switch s, the indication of ammeter A is 0.5A, the indication of ammeter A1 is 0.3A, find: (1) current through resistance R2; (2) power supply voltage; (3) resistance value of resistance R2

(1) The current through resistance R2 is I2 = i-i1 = 0.5a-0.3a = 0.2A; answer: the current through resistance R2 is 0.2A. (2) power supply voltage U = i1r1 = 0.3A × 20 Ω = 6V; answer: power supply voltage is 6V. (3) resistance R2 = ui2 = 6v0.2a = 30 Ω; answer: resistance R2 is 30 Ω