There are the following equipment on the experimental table: a power supply, an ammeter and a voltmeter, a switch, a sliding rheostat, two resistance boxes, fixed resistance and wires with known resistance values. It is required to select appropriate equipment from the experimental table and design an experiment to prove: "when the voltage at both ends of the resistance remains unchanged, the electric power consumed by the resistance is the same as that consumed by the resistance The resistance of the resistance is inversely proportional. Please draw the experimental circuit diagram, write the experimental steps, and design the data recording form

There are the following equipment on the experimental table: a power supply, an ammeter and a voltmeter, a switch, a sliding rheostat, two resistance boxes, fixed resistance and wires with known resistance values. It is required to select appropriate equipment from the experimental table and design an experiment to prove: "when the voltage at both ends of the resistance remains unchanged, the electric power consumed by the resistance is the same as that consumed by the resistance The resistance of the resistance is inversely proportional. Please draw the experimental circuit diagram, write the experimental steps, and design the data recording form

A: circuit diagram: experimental steps: (1) connect the adjusted circuit elements into the circuit according to the circuit diagram. (2) close the switch, adjust the resistance box indication to R, adjust the slide P of the sliding rheostat, so that the voltage indication is u, and the current indication is I, and record the data R, u, I in the table; (3) follow the steps (

As shown in the figure, the resistance of bulb L1 is 6 Ω and that of L2 is 4 Ω. When S1 is closed and S2 is open, the reading of ammeter is I1 = 0.8A; when S1 is open and S2 is closed, the reading of ammeter is I2 = 0.5A. Calculate the resistance and power supply voltage of bulb L3

When S1 is closed and S2 is closed, bulbs L1 and L2 are connected in series, and the total resistance of the circuit is r = R 1 + R 2 = 6 Ω + 4 Ω = 10 Ω. The voltage of the power supply is u = R total = 0.8A × 10 Ω = 8V. When S1 is open and S2 is closed, bulbs L1 and L3 are connected in series, and the total resistance of the circuit is r total '= UI' = 8V 0.5A = 16 Ω. The resistance of bulb L3 is R 3 = R total '- R 1 = 16 Ω - 6 Ω = 10 Ω. A: the resistance of bulb L3 is 10 Ω, and the power supply voltage is 8V