The current of a certain lightning is about 2 × 10 fourth power a, the voltage is about 10 eighth power V, and the discharge time is about 0.001s. What is the point power of this lightning? How much energy is released

The current of a certain lightning is about 2 × 10 fourth power a, the voltage is about 10 eighth power V, and the discharge time is about 0.001s. What is the point power of this lightning? How much energy is released

P=UI=2*10^4*10^8=2*10^12w,W=Pt=2*10^9J

The current of a certain lightning is about 2 × 10 ^ 4a, the voltage is about 1 × 10 ^ 8V, and the discharge time is about 0.001s?

Power p
=U*I
=10^8*2*10^4W
=2*10^12W
Work e
=Pt
=2*10^12*0.001J
=2*10^9J
About 555.6 kWh

The voltage at both ends of the electric cooker is 220 V and the current is 4 A. after 10 minutes of power on, what is its electric power? What is its resistance?

Solution
p=w/t
w=ui
therefore
w=220x4=800j
p=800/10
=80j
R=u/i
=220/4
=55 Euro

When the voltage at both ends of a fixed value resistor changes from 6V to 10V, the current flowing through the resistor increases by 0.1A______ Ω．

Let R be the resistance of the constant value resistor. From the meaning of the question, we can get 6vr + 0.1A = 10vr, and the solution is r = 40 Ω