A question about the complete square formula on the second day of junior high school is going to be urgent tonight Given (2006-a) (2004-A) = 2005, find the value of (2006-a) & sup2; + (2004-A) & sup2

A question about the complete square formula on the second day of junior high school is going to be urgent tonight Given (2006-a) (2004-A) = 2005, find the value of (2006-a) & sup2; + (2004-A) & sup2

Let x = 2004-A, then 2006-a = x + 2,
According to the meaning: X (x + 2) = 2005,
That is, x ^ 2 + 2x = 2005, (x + 1) ^ 2 = 2006
And (x + 2) ^ 2 + x ^ 2 = 2x ^ 2 + 4x + 4 = 2 (x + 1) ^ 2 + 2
SO 2 * 2006 + 2 = 4014

Two questions about complete square formula
1. If the result of the square of a polynomial is 4A ^ 2 + 12ab + m ^ 2, then m ^ 2=
2. Observe the following formula
（1+1）^2=1^2+2x1+1
(2+1)^2=2^2+2x2+1
(3+1)^2=3^2+2x3+1
... ...
(n+1)^2=n^2+2xn+1
Add the left and right sides of these n equations to get the formula:
1+2+3+4+5+...+n=

1: m=3b
2: 1+2+3+4+5+...+n=(n^2+n)/2