Find the relation of quadratic function satisfying the following conditions: the image passes through a (- 1,3) B (1,3) C (2,6) It's better to use a variety of methods. I'm in a hurry,

Let y = ax ^ + BX + C
Bring in the points above
The above method is not to think about optical computing, it is recommended to use it
Second, it is observed that
The point coordinates of AB are the same y but different X
So the axis of symmetry is x = 0
So we judge y = ax ^ 2
Then, the coordinate of point C is substituted to solve a

Given that the image of quadratic function passes through points a (0, - 1), B (1,0), C (- 1,2), find the quadratic function relation

y=ax²+bx+c
be
-1=0+0+c (1)
0=a+b+c (2)
2=a-b+c (3)
Then C = - 1
(2)-(3)
2b=-2
b=-1
a=-b-c=2
So y = 2x & # 178; - X-1

Given the quadratic function y = 8x ^ 2 - (k-1) x + k-7, when the value of K is, the quadratic function takes the y-axis as the axis of symmetry? Write out its functional relationship
I haven't learned the formula of symmetry axis. Can I use that one,

Method 1y = ax ^ 2 + H is the basic form of quadratic function with Y-axis as symmetry axis. Requirement: the coefficient of the first term is zero, h is the coordinate of moving down and up, and it is also the ordinate of the vertex of the quadratic function. So - (k-1) = 0, k = 1, then k-7 = - 6, so y = x ^ 2-6 method 2Y axis is x = 0 with Y-axis as symmetry axis

It is known that the quadratic function y = 8x & # 178; - (k-1) x + k-7. When the value of K is, the quadratic function takes the y-axis as the symmetry axis, and its relation is written out

The solution consists of quadratic function y = 8x & # 178; - (k-1) x + k-7
X = - B / 2A = - [- (k-1)] / 16 = (k-1) / 16
The quadratic function takes the Y axis as the symmetry axis
So the symmetry axis of the function image is x = 0
That is, (k-1) / 16 = 0
The solution is k = 1
So the quadratic function is y = 8x & # 178; - 6

Find the relation of quadratic function satisfying the following conditions: the image passes through a (- 1,3) B (1,3) C (2,6) It's better to use a variety of methods. I'm in a hurry,