An express train and a local train leave from station a and B at the same time. After 12 hours of meeting, the express train arrives at station B in 8 hours. How many hours does the local train have to go to reach station a?

An express train and a local train leave from station a and B at the same time. After 12 hours of meeting, the express train arrives at station B in 8 hours. How many hours does the local train have to go to reach station a?

It will take x hours for the local train to reach station A. according to the ratio of the topic, it is 8:12 = 12: X, & nbsp; 8x = 12 × 12, & nbsp; 8x = 144, & nbsp; & nbsp; X = 18. A: after 12 hours, the local train will take 18 hours to reach station a

It takes 8 hours for the express train from station a to station B, and 12 hours for the slow train from station B to station A. if the fast train and the slow train leave from station a and station B at the same time,
When we meet, the express train runs 180 kilometers more than the local train. How many kilometers do the two stations meet?

Car a takes 1 / 8 of the whole journey per hour, and car B takes 1 / 12 of the whole journey per hour
The speed ratio of a and B is: 1 / 8:1 / 12 = 3:2
The distance between station a and station B is: 180 △ (3-2) × (3 + 2) = 900 (km)

The distance between station a and station B is 96 kilometers. The express and local trains leave from station a at the same time. The express train arrives at station B in 40 minutes. It is known that the express train travels 12 kilometers more than the local train per hour. What is the speed of the express train and the local train

Let the speed of the local train be x km / h,
∴96/x-96/(x+12)=2/3
96×12/x(x+12)=2/3
96×36=2x(x+12)
x²+12x-48×36=0
(x+48)(x-36)=0
X = - 48, rounding off x = 36
12+x=12+36=48