Observe the sequence 6, 7, 9, 13, 21, then fill in the rule on the horizontal line (that is, the next number)

Observe the sequence 6, 7, 9, 13, 21, then fill in the rule on the horizontal line (that is, the next number)

6、7、9、13、21,37...
The first term plus 1,2,4,8,16... Is equal to the second term,
And 1,2,4,8,16. Are equal ratio sequences with common ratio 2

If the tolerance of a group of sequences is the general term formula of arithmetic sequence, how to find it? For example: 1,3,7,13,21,31, the difference of each number is 2,4,6

Using the method of accumulation
a2-a1=2=2*1
a3-a2=4=2*2
a4-a3=6=2*3
a5-a4=8=2*4
.
an-a(n-1)=2*(n-1)
Accumulation
an-a1=2[1+2+...+(n-1)]=n(n-1)
So an = n (n-1) + A1 = n (n-1) + 1 = n ^ 2-N + 1

For example:
1+4,2+6,5+10,10+16,17+24,（ )
Please give the answer and describe the rule

26+34
The first number starts with 1 and adds 1, 3, 5, 7
The second number starts with 4 and adds 2, 4, 6, 8
So the two numbers in the blank are 17 + 9 = 26 and 24 + 10 = 34