The rule is: from the second number, three times of each number is equal to the sum of the two numbers before and after it. What is the remainder of the 100th number divided by 3?

The rule is: from the second number, three times of each number is equal to the sum of the two numbers before and after it. What is the remainder of the 100th number divided by 3?

If a B C satisfies 3B = a + C, then a + C is a multiple of 3. If 3 can't divide a and the remainder of a / 3 is 1, then the remainder of C / 3 must be 2, and vice versa. Let's write a column of numbers (the sum of two numbers separated is 3, and only uses 1 and 2) 1 1 1 2 1 2 2 1 2 2 2 2... From the point of view of divisibility, the law of this column of numbers and the problem of

There is a column of numbers, the first number is 1, the second number is 3, from the third number, each number is equal to the difference between the larger one of the two numbers minus the smaller one, then the sum of the first 100 numbers in the column is equal to______ ．

The column numbers are 1, 3, 2, 1, 1, 0, 1, 1, 0 1, 1, 0, 1, starting from the fourth item, all appear in the order of "1, 1, 0", (100-3) △ 3 = 32 The sum of them is: 1 + 3 + 2 + 32 × (1 + 1 + 0) + 1 = 71

There is a column of numbers, A1, A2, A3 An, if A1 = - 1 / 2, from the second number, each number is equal to the reciprocal of the difference between 1 and the number in front of it. Write out the general law of an

N / 3 if the remainder is 1, then the number is - 1 / 2; if the remainder is 2, then the number is 2 / 3; if it is exactly divisible, then the number is 3