If the inner angle of the diamond is 120 ° and the length of its diagonal is 12cm, the perimeter of the diamond is The answer is 48CM or 2 √ 3, remember that there are two cases

If the inner angle of the diamond is 120 ° and the length of its diagonal is 12cm, the perimeter of the diamond is The answer is 48CM or 2 √ 3, remember that there are two cases

If 〈 a = 120 degrees, the diagonal BD of the opposite side is 12cm,
Then Bo = 6cm, ab = 6 * 2 / √ 3 = 4 √ 3, perimeter = 4 * 4 √ 3 = 16 √ 3cm
If AC = 12cm
AO=6cm,
AB = 2ao = 12cm, perimeter = 4 * 12 = 48CM

The inner angle of a diamond is 120 degrees. If the diagonal of bisecting this angle is 12cm, its perimeter is () cm
1. The inner angle of a diamond is 120 degrees. If the diagonal of bisecting this angle is 12cm, its perimeter is () cm
2. The area of the diamond is 24 square centimeters, one diagonal is 6cm long, the other diagonal is () cm long and the perimeter is () cm
3. If the perimeter of the diamond is 40 and the length of a diagonal is 10, what are the logarithm of two adjacent internal angles?

If the bisector angle of 1.48cm is 60 degrees, then if the triangle line is equilateral, then there is no 12 sides, then C = 12 * 4 = 48CM
If the 2.8cm bisector is divided into two congruent triangles, the area is 6 * 1 / 2, and if the other line is 24, the bisector is 8
20cm, one of which takes the side as a right triangle, the inner side is 5, and the perimeter is no 4 * 5 = 20

A diamond point guard 120 ° scoring method how long is the perimeter of the diamond when the diagonal is 12cm

The bisector of a diamond with an internal angle of 120 ° is the diagonal of the angle
It is easy to prove that the triangle formed by the two sides of the diagonal is a diamond is an equilateral triangle
Therefore, the side length of the diamond = the diagonal length of the diamond 120 ° angle = 12cm
Therefore, the diamond perimeter = 12 * 4 = 48 (CM)

The perimeter of the diamond is 48 cm and the length of a diagonal is 12 cm

∵ the perimeter of the diamond is 48CM, ∵ the side length of the diamond is 484 = 12cm, ∵ the length of a diagonal line is 12cm, ∵ the triangle formed by the diagonal line and the adjacent two sides is equilateral triangle, then the smaller inner angle of the diamond is 60 ° and the larger inner angle is 180 ° - 60 ° = 120 °. Therefore, the degree of the inner angle of the diamond is 120 °, 60 °, 120 ° and 60 °

The two diagonals of a diamond are 10 and 8 respectively. Take the straight line where the two diagonals are located as the coordinate axis to find the coordinates of the four vertices

(0,5), (0, - 5), (4,0), (- 4,0) or (5,0) (- 5,0) (0,4) (0, - 4)

The two diagonals of a diamond are 10 and 8 respectively. Take the coordinate axis of the straight line where the two diagonals are located to find the coordinates of the four vertices

If 10 is the horizontal axis, then: up (0,4); right (5,0); down (0, - 4); left (- 5,0)
If 8 is the horizontal axis, then: up (0,5); right (4,0); down (0, - 5); left (- 4,0)

As shown in the figure, the quadrilateral ABCD is a diamond, the diagonal AC and BD intersect at O, DH ⊥ AB at h, connect Oh, and verify: ∠ DHO = ∠ DCO

It is proved that: the ∵ quadrilateral ABCD is rhombic, ∵ od = ob, ∵ cod = 90 °, ∵ DH ⊥ AB, ∵ Oh = 12bd = ob, ∵ OHB = ∵ obh, and ∵ ab ∥ CD,