As shown in the figure, is ab = AE, BC = ed, AC = ad. (1) ∠ B = ∠ e known? Why? (2) If point F is the midpoint of CD, what is the positional relationship between AF and CD? Please give reasons

As shown in the figure, is ab = AE, BC = ed, AC = ad. (1) ∠ B = ∠ e known? Why? (2) If point F is the midpoint of CD, what is the positional relationship between AF and CD? Please give reasons

(1) The reason is: ∵ in △ ABC and △ AED, AC = ADAB = aebc = de ≌ ABC ≌ AED, ≌ B = E; (2) AF ⊥ CD, the reason is: ∵ AC = ad, f is the midpoint of CD, ≁ AF ⊥ CD

As shown in the figure, in the Pentagon ABCDE, BC = De, AE = DC, ∠ C = ∠ e, DM ⊥ AB is in M, try to explain that M is the midpoint of ab

It is proved that connecting AD and BD, ∵ BC = de ∠ C = EAE = DC, ≌ ade ≌ DBC (SAS), ≌ ad = BD, and ≔ DM ⊥ AB, ≌ m is the midpoint of ab

As shown in the figure, in the Pentagon ABCDE, ∠ BAE = 120 ° and ∠ B = ∠ e = 90 °
AB = BC, AE = De, find a point m and N on BC and de respectively, so that the perimeter of △ amn is the smallest, then the degree of ∠ amn + ∠ anm is ()
A.100° B.110° C.120° D.130°
Why C? Ask for an explanation

∠AMN+∠ANM=120°
Extend AB to a 'to make Ba' = AB, extend AE to a '' to make AE = EA '', then the intersection of a'a '' and BC, ED is the M and n,
∠AMN+∠ANM＝2∠A'+2∠A''=2(180-∠BAE)=120°