As shown in the figure, in the trapezoid ABCD, ad is parallel to BC, and the bisector ce of angle BCD intersects the midpoint e of ab

As shown in the figure, in the trapezoid ABCD, ad is parallel to BC, and the bisector ce of angle BCD intersects the midpoint e of ab

Suppose a DF is the height of BC side, make DFC a right triangle, then find out the trapezoid is isosceles trapezoid, then find out ADFG is square, then use Pythagorean theorem to find out CD = 2DF is OK!

If e is a point on BC, de = 2, CE = 1, then the area of square ABCD is ()
A. 3B. 3C. 4D. 5

As shown in the figure, ∵ in the right angle △ DCE, de = 2, CE = 1, ∠ C = 90 °, according to the Pythagorean theorem, CD = de2-ce2 = 22-12 = 3, ∵ the area of square ABCD is: CD · CD = 3

As shown in the figure, e is a point on the extension line of the edge BC of the square ABCD, and CE = AC, find the area of ace
Finding the area of △ ace
Title in Baidu search will see the picture. I can not upload a level
It's a copy. I don't understand.
The side length is 3cm

∵AB=3
∴AC=3√2
∴CE=3√2
∴S△ACE=1/2*CE*AB
=1/2*3√2*3=(9/2)√2cm²