If the height of a cuboid is reduced by 3cm, it becomes a cube. At this time, the surface area is reduced by 96cm2. What is the volume of the cuboid

If the height of a cuboid is reduced by 3cm, it becomes a cube. At this time, the surface area is reduced by 96cm2. What is the volume of the cuboid

Length of cuboid:
96÷4÷3
=24÷3
=8（cm）
Original height of cuboid: 8 + 3 = 11 (CM)
The original area of the cuboid:
8×8×11
=64×11
=704（cm³）
A: the volume of the original cuboid is 704cm;
If you agree with my answer, please click "adopt as a satisfactory answer" in the lower left corner. I wish you progress in your study!

The surface area of a cube is 54 square decimeters. What is the sum of all the edges of the cube?
Specific steps and ideas to Oh! Should be to understand a problem is not free to pass!

The surface area of cube is 6 × edge length × edge length
So the square of the edge length is 9. The edge length is 3. There are 12 edges, so the sum is 12 × 3 = 36

The surface area of a cube is 54 square decimeters. What is the sum of all the edges of the cube?

The base area of the cube is 54 △ 6 = 9 (square decimeter), and because of 3 × 3 = 9, its edge length is 3 decimeters, and the total edge length is 3 × 12 = 36 (decimeter). A: the sum of all edge lengths of the cube is 36 decimeters

The surface area of a cube is 54 square decimeters. What is the sum of all the edges of the cube? What is its volume?

The surface area is 54 square decimeters
Floor area = 54 △ 6 = 9 square decimeters
Side length = 3DM
Sum of edge length = 12 * 3 = 36dm
Volume = 3 * 3 * 3 = 27 cubic decimeter