The total area of the left figure is 1256 square centimeters. The overlapping area of the two rectangles is equal to one eighth of the area of the large rectangle and one sixth of the area of the small rectangle

The total area of the left figure is 1256 square centimeters. The overlapping area of the two rectangles is equal to one eighth of the area of the large rectangle and one sixth of the area of the small rectangle

Suppose that the area of large rectangle is x, the area of small rectangle is y, and the area of overlapping part is Z. then there are ① x + Y-Z = 1256; ② 8Z = x; ③ 6Z = y. from ② and ③, we can get X / y = 8 / 6 = 4 / 3. Substituting X and y of ② and ③ into ①, we can calculate the value of Z, so we can get the value of X and Y respectively according to ② and ③

There is a five ring graph. The diameter of each circle in the graph is about 8 cm, and the overlap between the two circles is about 32 square centimeters. The total area covered by the five ring graph is about 8 cm

8 * 8 * 3.14 / 4 * 5-4 * 32 = 123.2 square centimeter
Note: area covered by two adjacent circles = area of two circles - overlapping area
Covering area of five ring graph = 5 circle areas - 4 overlapping areas

The area of the overlapped part of the two pictures is equal to 2 / 11 of the area of the great circle. The area of the overlapped part is 12 square centimeters. What is the total area of the overlapped part
If the area of the overlap is 12 square centimeters, what is the total area of the two circles?

12*(11/2+7/3-1)=82
The area of the big circle is 12 * 11 / 2
The small circle is 12 * 7 / 3
Big circle + small circle - overlap