There is a 2 m × 1.5 m rectangular tablecloth, which is laid on a rectangular table. The cloth curtain of the same width is hung down all around. The area of the table is just half of the area of the tablecloth. The length and width of the table are calculated

There is a 2 m × 1.5 m rectangular tablecloth, which is laid on a rectangular table. The cloth curtain of the same width is hung down all around. The area of the table is just half of the area of the tablecloth. The length and width of the table are calculated

If the vertical width is x m, the
(2-X)(1.5-X)=1/2*2*15
The solution is X1 = 0.5, X2 = 3
2-0.5=1.5,1.5-0.5=1
The table is 1.5m long and 1m wide

There is a rectangular table, 6 feet long and 3 feet wide. There is a cloth, which is twice the area of the table top
What's the length and width of the tablecloth?

The length of cloth is a, the width is B, and each side is down C
a×b=36
b=6+2c
a=3+2c
A = 4.685
b=7.685

The table top of a table is 6m in length and 4m in width. The area of the tablecloth is twice that of the table top. If the tablecloth is laid on the table, the length of each side is the same. Find the length and width of the tablecloth

Let the length of each side of the tablecloth be XM. According to the meaning of the problem, we get (6 + 2x) (4 + 2x) = 2 × 4 × 6. The solution is X1 = - 6 (not suitable for the meaning of the problem, omit), X2 = 1, so 6 + 2x = 8, 4 + 2x = 6. Answer: the length and width of this tablecloth are 8m and 6m respectively