If the line y = KX + 1 moves 1 unit to the right, and then moves 2 units to the top, it just passes through the point (- 2,1), then K

If the line y = KX + 1 moves 1 unit to the right, and then moves 2 units to the top, it just passes through the point (- 2,1), then K

Y + 2 = K (x + 1) + 1, so k = - 2

Given the parabola y = x ^ 2-2x-3, the parabola image can be shifted several units to the right to make the translated image pass through the coordinate origin?
And directly write another intersection point between the translated image and the X axis

Answer: parabola y = x & # 178; - 2x-3 = (x-1) & # 178; - 4 symmetry axis X = 1, vertex (1, - 4) let the parabola after translation be y = (x + a) & # 178; - 4 pass through the origin (0,0), and substitute it into: A & # 178; - 4 = 0, so: a = - 2 or a = 2, because it is translation to the right, so: a = - 2, so: translation to the right is 2-1 = 1 unit

Given the parabola y = AX2 + BX + C as shown in the figure, then the root of the equation AX2 + BX + C-8 = 0 is ()
A. There are two unequal positive real roots B. There are two different signed real roots C. There are two equal real roots d. There are no real roots

∵ y = AX2 + BX + C, the ordinate of the image vertex is 8, and the image of y = AX2 + BX + C-8 can be obtained by moving down 8 units. At this time, there is an intersection point between the parabola and the x-axis, and the equation AX2 + BX + C-8 = 0 has two equal real roots