Let the tangent of the curve y = FX at point (1, F1) be parallel to the X axis, then the tangent equation

Let the tangent of the curve y = FX at point (1, F1) be parallel to the X axis, then the tangent equation

The tangent equation is y = F1

It is known that the two roots of the equation y = AX2 + BX + C are - 1 and 3 respectively. The parabola y = AX2 + BX + C has an intersection n (2, - 3) with the straight line y = KX + m passing through point m (3,2)
(1) The analytic formula of straight line and parabola
(2) The two intersections of the parabola and X-axis from left to right are a and B respectively, and the vertex is p. if q is the point on the parabola different from a, B and P, and the angle QAP is equal to 90 degrees, the coordinates of q-point can be obtained

The two roots of the straight line k = (2 + 3) / (3-2) = 5y-2 = 5 (x-3) 5x-y-13 = 0y = ax ^ 2 + BX + C are respectively - 1 and 3a-b + C = 0. (1) 9A + 3B + C = 0. (2) the parabola y = AX2 + BX + C and the straight line y = KX + m have an intersection n (2, - 3) 4A + 2B + C = - 3. (3) a = 1, B = - 2, C = - 3

It is known that the two equations ax & # 178; + BX + C = 0 are - 1 and 3 respectively, the straight line y = KX + m passes through the point m (3,2), and the parabola y = ax & # 178; + B
X + C and the line y = KX + m intersect at the point n (2,3). The analytic expressions of the line and parabola are obtained

The two of ∵ ax & # 178; + BX + C = 0 are - 1 and 3 ∵ a * (- 1) &# 178; + b * (- 1) + C = 0, i.e. A-B + C = 0. (1) a * 3 & # 178; + b * 3 + C = 0, i.e. 9A + 3B + C = 0. (2) ∵ straight line y = KX + m crosses point m (3,2) ∵ 2 = 3K + M. (3) ∵ parabola y = ax & # 178; + BX + C and straight line y = KX + m intersect point n (2,3) ∵ a * 2 & # 178; + b * 2

It is known that the two roots of the equation AX ^ 2 + BX + C = 0 are - 2 / 3 and 1 / 2 respectively, and the parabola y = ax ^ 2 + BX + C has an intersection Q (- 1, - 3) with the straight line y = KX + m of point P (1,3 / 2). The analytical expressions of the straight line and parabola are obtained

Substituting points (- 2 / 3,0), (1 / 2,0) and (- 1, - 3) into y = ax ^ 2 + BX + C, the values of a, B and C can be solved; substituting points (1,3 / 2) and (- 1, - 3) into y = kx + m, the values of K and M can be solved