Find the area of SiNx enclosed by [0,2 π] and x-axis

Find the area of SiNx enclosed by [0,2 π] and x-axis

Using integral: area = ∫ sinxdx, upper limit 2 π, lower limit 0, and ∫ sinxdx = 0.5x-0.25sin2x + C, C is constant, [0.5x-0.25sin2x + C], 2 π is subtracted from 0 to get π, so the area obtained is π

As shown in the figure is a side expanded view of a three-dimensional figure, calculate its total area and volume
What kind of figure is it

Quarter π × 10 2; × 8 = 200 π cubic centimeter (volume) total area: quarter π × 10 2; × 2 + quarter × 2 π × 10 × 8 + 10 × 8 × 2 = 90 π + 160 square centimeter and I

As shown in the figure is a side expansion of a solid figure, calculate its total area and volume

(1) Its total area is: 14 × (3.14 × 102 × 2 + 3.14 × 2 × 10 × 8) + 10 × 8 × 2, = 14 × (628 + 502.4) + 160, = 14 × 1130.4 + 160, = 282.6 + 160, = 442.6 (square centimeter), (2) its volume is: 14 × 3.14 × 102 × 8 = 628 (cubic centimeter)

As shown in the figure, there is a small cube on the large cuboid. Find the surface area and volume of the solid figure
centimeter

Volume 184
Surface area 252