The solution dy / DX + 1 / 3Y = 1 / 3 * (1-2x) y ^ 4 I feel the answer is wrong,

The solution dy / DX + 1 / 3Y = 1 / 3 * (1-2x) y ^ 4 I feel the answer is wrong,

dy/dx=-1/3y+1/3(1-2x)y^4
dy/dx=-1/3y+1/3y^4-2/3xy^4
dy=(-1/3y+1/3y^4-2/3xy^4)dx
Integral of both sides at the same time is as follows:
y=-1/3xy+1/3xy-1/3x^2y^4+t(t=0,1,2,3.)

1m / S = km / S; 1km / h = km / S

1m/s=0.001km/s
1km/h=1/3.6m/s
1m/s=3.6km/h

Find the general solution of the following homogeneous equation (x ^ 3 + y ^ 3) dx-3xy ^ 2dy = 0

Use variable substitution to simplify the solution. Economic mathematics team to help you solve. Please evaluate in time

For example: 10M / min =? Km / h

1m/s=3.6KM/h

General solution of (y + 1) ^ 2dy / DX + x ^ 3 = 0

(y+1)^2dy/dx+x^3=0
(y+1)^3/3=-x^4/4+C

If the length of the circular arc is 50cm and the center angle of the circle is known to be 200 degrees, the radius of the circle (accurate to 0.1cm) can be calculated

14.3CM

The general solution of the differential equation (x ^ 3 + y ^ 3) dx-3xy ^ 2dy = 0 does not include y = 0. Is C in the general solution any constant?

I don't understand

Given that the arc length of the center angle of 1 ° is 1cm, then the radius of the circle is____

Given that the arc length of 1 ° is 1cm, the radius of the circle is 180 / π cm
Given that the arc length of 1 ° is 1cm, the circumference of the circle is 360cm
Radius = 360 ﹣ π ﹣ 2 = 180 ﹣ π = 180 / π cm

Is (x ^ 3 + y ^ 3) dx-3xy ^ 2dy = 0 a total differential equation

Is (x ^ 3 + y ^ 3) dx-3xy ^ 2dy = 0 (1) a total differential equation?
no
Because: &; (x ^ 3 + y ^ 3) / &; y = 3Y ^ 2 is not equal to &; (- 3xy ^ 2) / &; X = - 3Y ^ 2,
Therefore: (1) it is not a total differential equation

In a circle of 4 / π, the arc length corresponding to the central angle of 45 ° is equal to the filling length

1/16