Factorization factor: x2-2xy + y2-4=______ ．

Factorization factor: x2-2xy + y2-4=______ ．

X2-2xy + y2-4 = (X-Y) 2-4 = (X-Y + 2) (x-y-2). So the answer is: (X-Y + 2) (x-y-2)

Given that X-Y + 1 and x 2 + 8 x + 16 are opposite to each other, find the value of x 2 + 2XY + y 2
x2-4xy+4y2-10x+20y+25
Factorization

49
(x-2y-5)*2

Given that | X-Y + 1 | and X2 + 8x + 16 are opposite to each other, find the value of x2 + 2XY + Y2

∫||x-y + 1|and x2 + 8x + 16 are opposite numbers, and |||x-y + 1|and (x + 4) 2 are opposite numbers, that is ||x-y + 1| + (x + 4) 2 = 0, | X-Y + 1 = 0, x + 4 = 0, the solution is x = - 4, y = - 3. When x = - 4, y = - 3, the original formula = (- 4-3) 2 = 49