分解因式:x2-2xy+y2-4=______.

分解因式:x2-2xy+y2-4=______.


x2-2xy+y2-4=(x-y)2-4=(x-y+2)(x-y-2).故答案為:(x-y+2)(x-y-2).



已知│x-y+1│與x2+8x+16互為相反數,求x2+2xy+y2的值.
x2-4xy+4y2-10x+20y+25
分解因式


49
(x-2y-5)*2



已知|x-y+1|與x2+8x+16互為相反數,求x2+2xy+y2的值.


∵|x-y+1|與x2+8x+16互為相反數,∴|x-y+1|與(x+4)2互為相反數,即|x-y+1|+(x+4)2=0,∴x-y+1=0,x+4=0,解得x=-4,y=-3.當x=-4,y=-3時,原式=(-4-3)2=49.