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直線l1的方程為x+2y-2=0,將直線l1繞原點按逆時針方向旋轉90°得到直線l2,l2的斜率為:2,直線l1上的(2,0)繞原點按逆時針方向旋轉90°得到直線l2的點(0,2),所以l2的方程是2x-y+2=0故答案為:2x-y+2=0
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