As shown in the figure, in the right angle △ ABC, CD is the height on the hypotenuse AB, ∠ BCD = 35 °, find: (1) the degree of ∠ EBC; (2) the degree of ∠ a

As shown in the figure, in the right angle △ ABC, CD is the height on the hypotenuse AB, ∠ BCD = 35 °, find: (1) the degree of ∠ EBC; (2) the degree of ∠ a

(1) (2) in the right angle △ ACD, ∠ a + ∠ ACD = 90 ° and ∫ ACD + ∠ BCD = 90 ° and ∫ a = ∠ BCD = 35 ° respectively

As shown in the figure, the quadrilateral defg is the inscribed rectangle of △ ABC. If the high line ah of △ ABC is 8cm long and the bottom edge BC is 10cm long, let DG = xcm, de = YCM, and find the functional relationship of Y with respect to X

Let ah and DG intersect at point m, then am = ah-mh = 8-y, ∵ DG ∥ BC, ∥ ADG ∥ ABC, ∥ amah = dgbc, that is, 8 − Y8 = X10

With BAC = 90 ° AB = 8ac = 6, defg is the inscribed rectangle of ABC, points E and F are on BC, point D is on AB, and point G is on AC, and de: EF = 4:5 is used to calculate the area of the rectangle
ABC is a triangle

It's not convenient for me to upload pictures now, so let's narrate!
Let DG = EF = 5a, then Ag = 3A is known from Pythagorean theorem, so CG = 6-3a. Then GF = 0.8 * (6-3a) is known from Pythagorean theorem, because GF = de = 4A, 0.8 * (6-3a) = 4A
So a = 0.75 has s = 5A * 4A = 11.25 (i.e. 45 / 5)