If the three sides ABC of triangle satisfy the condition AA + BB + CC + 338 = 10A + 24B + 26c, try to judge the shape of ABC of triangle

If the three sides ABC of triangle satisfy the condition AA + BB + CC + 338 = 10A + 24B + 26c, try to judge the shape of ABC of triangle

The original formula can be changed to a & sup2; + B & sup2; + C & sup2; + 338 = 10A + 24B + 26ca & sup2; + B & sup2; + C & sup2; + 338 - (10a + 24B + 26c) = 0A & sup2; + B & sup2; + C & sup2; + 338 - (10a + 24B + 26c) = (a-5) ^ 2 + (B-12) ^ 2 + (C-13) ^ 2 = 0a-5 = 0b-12 = 0C = 13 = 0A = 5, B = 12, C = 135 ^ 2 + 12 ^ 2 =

If the triangle ABC satisfies the condition AA + BB + CC + 338 = 10A + 24B + 26c, then what is the triangle

From the formula in the question, we can get: (a-5) ^ 2 + (B-12) ^ 2 + (C-13) ^ 2 = 0
Furthermore, we get a = 5, B = 12, C = 13
And because: A ^ 2 + B ^ 2 = C ^ 2
So the triangle ABC is a right triangle with C as the right angle