In △ ABC and △ def, angle B = angle e = 90 °, angle a = 34 °, angle d = 56 ° AC = DF, then △ ABC and △ def_____ The reason is_______

In △ ABC and △ def, angle B = angle e = 90 °, angle a = 34 °, angle d = 56 ° AC = DF, then △ ABC and △ def_____ The reason is_______

Congruent triangles, reason: triangles are equal and hypotenuses are equal

In Δ ABC and Δ def, if ∠ B = ∠ e = 90, ∠ a = 34, ∠ d = 56, AC = DF, are Δ ABC and Δ def identical? Why?

The reasons are as follows: because ∠ B = ∠ e = 90, ∠ a = 34, ∠ d = 56. So ∠ f = 180 - ∠ e - ∠ d = 34. So ∠ f = a
In Δ ABC and Δ def: ∠ B = e ∠ f = a AC = DF, so Δ ABC and Δ def are congruent

If the angle DEF is obtained by the angle ABC translation, and the angle ABC is equal to 56 degrees, what is the angle def equal to

Because it is translational, so the size remains unchanged at 56 degrees

In the triangle ABC, D and E are the midpoint of BC and ab respectively, ad and CE intersect at the point OAB equals 3, AC = 4, BC = 5, OE =?
This is the problem of the median line lesson

For high AF of triangle ABC, in ADF of RT triangle ad = 2DF, so ad = BC + 2bd, and BDE of triangle is regular triangle BC + BD = ad-bd = AE
The original question is right. If you change it, it will be wrong