The waist length of an isosceles triangle is 2, the vertex angle is 120 ° and the area of its circumcircle is calculated As the title

The waist length of an isosceles triangle is 2, the vertex angle is 120 ° and the area of its circumcircle is calculated As the title

Make a vertical line across the vertex and extend it to the circle. Because it is an isosceles triangle, this vertical line is the diameter of the circle
Because the waist length of an isosceles triangle is 2 and the vertex angle is 120 degrees
So the degree of the angle divided by this diameter is 60 degrees
So the diameter of the circle is 4 (the side opposite 30 degrees is half of the hypotenuse)
So the area is pie r = 4 pie

The waist length of an isosceles triangle is 2cm, and the vertex angle is equal to 120 ° to find the diameter of its circumcircle

As shown in the figure, connect OA, ob, OC ∵ AC = BC ∵ arc AC = arc BC ∵ OC and divide AB vertically
The equilateral triangles are as follows: ∧ OCA = ∧ OCB = 60 ° OC = OA ∧ OAC
∴OA=2 ∴2R=4

It is known that the waist length of an isosceles triangle is 3cm and the vertex angle is 120 degrees. Find the diameter of the circumcircle of the triangle

The center of the circumscribed circle is the intersection of the vertical bisectors of the sides of the triangle. Let ABC be the triangle connecting the center of the circle OA ob, and AOB be the regular triangle (R is equal to 60 degrees), so the diameter is 6
I hope my answer will help you!