In the triangle ABC, D is the midpoint of AB, if AC = 15, BC = 8. CD = 8. 5, it is proved that the triangle ABC is a right triangle

In the triangle ABC, D is the midpoint of AB, if AC = 15, BC = 8. CD = 8. 5, it is proved that the triangle ABC is a right triangle


Extend CD to F, make FD = 8.5, join dB, then BD = AC = 17 (parallelogram). Then 17 ^ 2 = 15 ^ 2 + 8 ^ 2. Then CFB is a right triangle. Because acbf is a parallelogram, ABC is a right triangle



As shown in the figure, in the triangle ABC, ad is perpendicular to point D, angle B = 45 degrees, angle c = 30 degrees, BC = 60, find the length of AD


30（√3-1）

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