Draw a plane rectangular coordinate system and calculate the area 1 a (- 6,0) B (0,8) C (0,3) s △ ABC 2 a (6,0) B (0,8) C (- 4,0) s △ ABC 3 A (- 4,3) B (- 4,2) C (5,2) for s △ ABC 4 a (5,5) B (- 3, - 3) C (16,0) where AB passes through the origin, find s △ ABC The area of sabcd can be calculated from the vertex a (0,0) B (2,5) C (7,7) d (4,0) of 5 ABCD quadrilateral

Draw a plane rectangular coordinate system and calculate the area 1 a (- 6,0) B (0,8) C (0,3) s △ ABC 2 a (6,0) B (0,8) C (- 4,0) s △ ABC 3 A (- 4,3) B (- 4,2) C (5,2) for s △ ABC 4 a (5,5) B (- 3, - 3) C (16,0) where AB passes through the origin, find s △ ABC The area of sabcd can be calculated from the vertex a (0,0) B (2,5) C (7,7) d (4,0) of 5 ABCD quadrilateral

1.S=1/2*BC*OA=15
2.S=1/2*AC*OB=40
3.S=1/2*AB*BC=4.5
4.S=S△AOC+△BOC=1/2*OC*YA+1/2*OC*YB=64
5. Sabcd = s △ ABC + s △ ADC make BC angle of straight line, Y-axis and E (0,4.2)
SABCD=S△ACE-S△ABE+S△ADC=1/2*OE*XC-1/2OE*XB+1/2*AD*YC=24.5

Establish the plane rectangular coordinate system, draw △ ABC with points a (0, - 2), B (- 4,0), C (3,0) as the vertex in the coordinate system, and calculate the area of △ ABC

Draw your own picture. I'll help you with the area
S=7×2÷2=7

If there are a (- 2, - 1), B (- 4,3), C (0,0) in the plane rectangular coordinate system, the area of triangle ABC is ()
A. 5B. 6C. 8D. 3

As shown in the figure, △ ABC area = 4 × 4-12 × 4 × 2-12 × 1 × 2-12 × 4 × 3 = 16-4-1-6 = 16-11 = 5

In the plane rectangular coordinate system, there is a (0,1) B (2,1) C (3,4) d (2,4) 1. The equation for finding the circumscribed circle m of triangle ABC. 2. If the midpoint of the chord cut by the circle m is exactly the point D, the equation for finding the line

Let (x-a) &# 178; + (y-b) &# 178; = R & # 178; the linear equation of the vertical line in line AB is x = 1; the linear equation of the vertical line in line AC is x + y = 4; the center of the circle is (1,3) and the radius is the root sign 5; the equation (x-1) &# 178; + (Y-3) &# 178; = 5, because the line passing through the center of the circle and D is perpendicular to the line, and the linear equation is x + y-6 = 0