Is there a relationship between the formula of parallelogram and diagonal? Is there a diagonal in the area of parallelogram except the low times the high?

It doesn't matter. If it's a diamond, you can divide the area by two

The volume formula of a circle into a rectangle, and the volume formula of a square into a parallelogram

Is it area
If you understand this way, divide a circle into numerous small sectors, and then interlace the small sectors up and down to form a shape similar to a rectangle, you can know that the width of the rectangle is the radius of the circle, and the length is half of the circumference of the circle. According to the area of the rectangle, length * width = (2 μ R / 2) * r, so the area formula of the circle can be deduced as R square
A square can be changed into a parallelogram, and the parallelogram can be cut into a rectangle, so that the area is the bottom * height

What in the area formula of parallelogram is equivalent to what of circle?

A circle is cut into several equal parts along the radius, and then a series of central angles are occluded with each other to form an approximate rectangle. The length is half of the circumference of the circle, and the width is the radius of the circle, so s length = a * b = π R * r = π R & sup2;
Suppose the length of a rectangle is a and the width is B
Rectangle area = a * B
A = circumference / 2 = 2B π / 2 = π B
Rectangle area = a * b = π b * b = π B & sup2;

In the triangle rule, are the three forces connected end to end or two arrows pointing together

If there are "two arrows" together, it is "the combination of forces". Find out the force between the two tails and the two arrows, which is the resultant force
If there are no two arrows together, the resultant force is zero

How to find the indefinite integral of sin (the square of x)?

Sin (x) / X for indefinite integral
Indefinite integral cannot be expressed by elementary function

SiNx is expanded as a power series, because it converges and can be integrated term by term

A problem about indefinite integral ∫ sin square xcos xdx / (1 + sin square x)
Such as the title

∫ [(SiNx) ^ 2 * cosx] / [1 + (SiNx) ^ 2] DX = ∫ [(SiNx) ^ 2] / [1 + (SiNx) ^ 2] d (SiNx) let u = SiNx have the original formula = ∫ u ^ 2 / (1 + u ^ 2) Du = ∫ [1-1 / (u ^ 2 + 1)] Du = ∫ Du - ∫ 1 / (u ^ 2 + 1) Du = u-arctanu + C = SiNx arctan (SiNx) + C

Indefinite integral of ∫ 4 / 1-sin ^ 2T

Just look up the basic integral formula
Because 4 / (1-sin & sup2; t) = 4 / cos & sup2; t = 4sec & sup2; t,
So ∫ 4 / (1-sin & sup2; t) DT = ∫ 4sec & sup2; t DT = 4 ∫ sec & sup2; t DT = 4tant + C

Find indefinite integral ∫ 1 / (x ^ 2 + 4x + 5) DX

The key to solve the problem: the second kind of integral method. Please accept!

Is there a relationship between the formula of parallelogram and diagonal? Is there a diagonal in the area of parallelogram except the low times the high?