If n is a positive integer, the value of (n + 11) ² - N & #178; can always be divided by K, then K is equal to the multiple of () a 11 b 22 C 11 or 22 D 11

If n is a positive integer, the value of (n + 11) ² - N & #178; can always be divided by K, then K is equal to the multiple of () a 11 b 22 C 11 or 22 D 11

D

Is there a real number a such that f (x) = a (x) 2 + BX + B-1 (a is not equal to 0) has two different zeros for any real number B?

That is, the quadratic equation AX ^ 2 + BX + B-1 = 0 has two unequal real roots
Discriminant > 0
b^2-4a(b-1)>0
b^2-4ab+4a>0
For any real number B, the inequality holds, that is, the equation B ^ 2-4ab + 4A = 0, and the discriminant is constant

In △ ABC, BD bisects ∠ ABC and connects ed to intersection AB at point E. ∠ a = 65 °∠ ABC = 56 °. Calculate the degree of ∠ BDE and ∠ BDC
∠BDE＝28° ∠BDC＝93°

Are you missing a condition? According to your answer, ED should be parallel to BC, or be = ed
∠BDE = ∠DBC = 1/2(∠ABC=56°)= 28°
However, BDC can be obtained
∠BDC = ∠A+ ∠ABD = 65°+28°=93°