"People destroy natural resources at will" is illustrated by a living example To give examples It's not the consequence

Local people living in South America burn precious virgin forests to get open land for farming. When the nutrients in the land are used up, they abandon the land to choose new forests, burn, farm and discard them. In this way, the Amazon rainforest will be destroyed
Some people in China cut down on the forest and so on

Examples of people destroying natural resources at will
But not too long, about 60 ~ 100 words

The atmospheric environment is deteriorating. The main manifestations are: the increase and aggravation of climate disasters, global warming, melting of glaciers, the corresponding rise of sea level, the threat of coastal lowlands inundated by sea water; the change of atmospheric composition that is not conducive to human beings, the increase of carbon dioxide, the decrease of ozone layer concentration to alleviate ultraviolet radiation, and the stench over the earth's poles

In today's real life, there are many actions that destroy the environment. Can you give two examples?
example!

Factories discharge sewage, waste batteries, domestic waste, water saving, kitchen waste, disposable medical equipment, felling trees

A monument with a mass of 100t is placed on a rectangular foundation stone with a height of 1m and a density of 2 * 10 cubic kg / m3. If the ground pressure can not exceed 1.45 * 10 quintic PA, what is the minimum ground area of the foundation stone?
2 AB two objects are stacked on the horizontal ground. It is known that the area of a is 0.6 square decimeter, the mass of B is 50 kg, the bottom area is 50 square decimeter, and the pressure of a to B is the fourth power PA of 6 * 10
3. The cube copper block with mass of 8.9kg is placed in the center of the horizontal plane, and its pressure on the table top is respectively?
The more detailed the answer is, the more + 50 points will be given at the end
The answers are appalling

1. If the area of the foundation stone is s, its mass is 1 * s * 2000 = 2000s = 2st, the total mass of the monument and the foundation stone is (100 + 2S) t, so the pressure on the ground is (100 + 2S) * 1000 * 9.8/s = 7.815m2. The gravity of a is 60000pa * (0.6 / 100) m2 = 360nb, and the gravity of B is 50 * 9.8 = 490N

Physical atmospheric pressure problem
1. The first experiment to measure atmospheric pressure accurately was completed by Italian scientist Deli. The atmospheric pressure he measured is equivalent to the pressure produced by a high mercury column. A standard atmospheric pressure is equal to pa

76m 1 × 10 quintic

When a container with a bottom area of 800 square centimeters and a volume of 0.038 cubic meters is filled with a certain liquid, its pressure on the horizontal table is 5000 Pa. if the container itself weighs 20 N, the density of the liquid is (g = 10 N / kg)

I'll tell you the method. If you give the answer directly, you won't know how to think
adopt
Pressure × base area = pressure
There are two parts to this pressure,
Pressure = gravity of liquid + gravity of container
Calculate the gravity of the liquid
The gravity of the liquid is calculating the mass of the liquid by G = mg
Through the mass, volume, density relationship
Density = mass / volume
Calculate the density

The container weighs 5.3n and has a bottom area of 40 square centimeters. It contains 1500 cubic centimeters of water with a depth of 30 cm. The container is placed on a horizontal table with an area of 2000 square centimeters
1. The pressure and pressure of water on the bottom of the container
2. The gravity of water
3. The tabletop is under the pressure of the container

1. P1 = pwater * g * H = 1.0 * 10 ^ 3kg / cm ^ 3 * 10N / kg * 0.3m = 3 * 10 ^ 3paf1 = P1 * s = 3 * 10 ^ 3PA * 40 * 10 ^ - 4m ^ 2 = 12n2, g = mg = pwater * V * g = 1.0 * 10 ^ 3kg / cm ^ 3 * 1500 * 10-6m ^ 3 * 10N / kg = 15n3, P2 = F2 / S1 = (gwater + G container) / S1 = (15N + 5.3n) / 40 * 10 ^ - 4m ^ 2 = 5075paf2 = g

Physical pressure exercises

If two uniform solid cubes A and B are placed on the horizontal ground, their respective pressures on the ground are equal
After cutting off the parts with equal height in the horizontal direction on a and B, the remaining parts will be cut off
A
The volume of a may be equal to that of B
B
The mass of a may be less than that of B
C
The pressure of a on the ground must be equal to the pressure of B on the ground
D
The pressure of a to the ground must be greater than that of B to the ground

There is a monument, with a mass of 90t, standing on the top of a rectangular cornerstone, 2m, with a density of 2.5 × 10 ^ 3kg / m3. If the maximum pressure that the ground can bear is 7.0 × 10 ^ 4pa, what is the area of the cornerstone at least (G is 10N / kg)

Take the critical case calculation (that is, the pressure of the foundation stone on the ground is just equal to the maximum pressure that the ground can bear)
In this critical case, the bottom area of the foundation stone is s, then
The mass of foundation stone is m = ρ * s * H
PDI = (M base + m tablet) g / S
So 7.0 * 10 ^ 4 = (2.5 * 10 ^ 3 * s * 1.2 + 90 * 1000) * 10 / S
It is found that the minimum critical bottom area is s = 22.5 square meters

A cylindrical tube with a cross-sectional area of 100cm2 and openings at both ends is blocked by a light sheet AB which is slightly larger than the bottom surface of the circular tube at the lower end of the tube, and then it is vertically placed in a container containing clear water, and water can not penetrate into it. If the upward pressure of water on the sheet is 19.6n, then: (1) how deep is the sheet immersed in water? (2) What is the maximum volume of water that can be injected into the cylindrical tube to ensure that the sheet AB does not fall off? (sheet mass not included)

(1) The upward pressure of water on the thin plate: P = FS = 19.6n100 × 10-4m2  1960pa,  P = ρ GH  H = P ρ g = 1960pa1 × 103kg / m3 × 9.8n/kg = 0.2m; (2) according to the condition of two force balance, in order to ensure that the thin plate AB does not fall off, the maximum gravity of water injected into the cylindrical tube is equal to the upward pressure of the thin plate, that is, g = 19.6n9.8n/kg = 2kg,  ρ = MV  The volume of water injected into the tube: v = m ρ = 2kg1 × 103kg / m3 = 2 × 10-3m3. Answer: (1) the depth of the sheet immersed in the water is 0.2m; (2) to ensure that the sheet AB does not fall off, the maximum volume of water injected into the cylindrical tube is 2 × 10-3m3

"People destroy natural resources at will" is illustrated by a living example To give examples It's not the consequence