How to prove the Pythagorean theorem of square of a + square of B = C with the paper of right triangle

How to prove the Pythagorean theorem of square of a + square of B = C with the paper of right triangle

The area of a square: C * C = C & # 178; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; equivalent to the area of one or four triangles + the area of the middle square & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & n

According to Pythagorean theorem, if C = 34, a: B = 8:15, find a, B

Let a = 8x, B = 15x, then (8x) ^ 2 + (15x) ^ 2 = 34 ^ 2, x = 2, so a = 16, B = 30

A + B = C. why is 6 + 8 not equal to 100, please
6 + 8 should be 100

6 + 8 should wait 10